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Herzog Competition - 2000

THE TWENTY-EIGHTH HERZOG PRIZE EXAMINATION

November 4, 2000

Problem 1

The recursion formula f ( n + 2 ) = f ( n + 1 ) + f ( n ) defines the Fibonacci sequence in case we start with the conditions f(0) = f(1) = 1. Of course, if we start with other integral values for f(0) and f(1), different sequences will result. Some of these sequences will contain a multiple of 5 (for example 1,1,2,3,5,… or 8,13,21,34,55,…). However, the starting values f(0) = 1, f(1) = 3 result in the sequence 1,3,4,7,11,18,29,…, and it’s not immediately clear whether a multiple of 5 will ever make an appearance.

Determine how many terms should be calculated in order to ascertain whether or not such a sequence will contain a multiple of 5 for arbitrary starting values.

Problem 2

Determine the locus of all points P(x,y) that satisfy

( x − 4 ) 2 + y 2 − x 2 + ( y + 3 ) 2 = 7

Problem 3

Can a plane circle pass through exactly three points with rational coordinates?

Problem 4

Let p and q be twin primes greater than 3. Show that p 2 + q 2 − 2 is divisible by 72.

Problem 5

Each number in the triple {112,518,322} is divisible by 14. Furthermore, the determinant

| 1 1 2 5 1 8 3 2 2 | = 14

Prove the general result: Any common factor of n arbitrary n-digit numbers is also a factor of the analogously formed n×n determinant.

Problem 6

Let c>1, and define F ( t ) = ∫ 1 c d x ( x 2 + t ) . Prove that F(t) is continuous at t = 0.